质能方程：$E=mc^2$
$$E=mc^2$$
公式$\sum_{i = 1}^m \mu(in)$公式
公式\(\sum_{i = 1}^m \mu(in)\)公式
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#include<cstdio> #include<cmath> #include<iostream> #include<algorithm> #include<climits> #include<string> #include<cstring> #include<cstdlib> #include<vector> #include<queue> #include<map> #include<set> #define LL long long using namespace std; inline char nc(){ /* static char buf[100000],*p1=buf,*p2=buf; if (p1==p2) { p2=(p1=buf)+fread(buf,1,100000,stdin); if (p1==p2) return EOF; } return *p1++; */return getchar(); } inline void read(int &x){ char c=nc();int b=1; for (;!(c>='0' && c<='9');c=nc()) if (c=='-') b=-1; for (x=0;c>='0' && c<='9';x=x*10+c-'0',c=nc()); x*=b; } inline void read(LL &x){ char c=nc();LL b=1; for (;!(c>='0' && c<='9');c=nc()) if (c=='-') b=-1; for (x=0;c>='0' && c<='9';x=x*10+c-'0',c=nc()); x*=b; } inline void read(char &x){ for (x=nc();!(x=='('||x==')');x=nc()); } inline int read(char *s) { char c=nc();int len=1; for(;!(c=='('||c==')');c=nc()) if (c==EOF) return 0; for(;(c=='('||c==')');s[len++]=c,c=nc()); s[len++]='\0'; return len-2; } int wt,ss[19]; inline void print(int x){ if (x<0) x=-x,putchar('-'); if (!x) putchar(48); else { for (wt=0;x;ss[++wt]=x%10,x/=10); for (;wt;putchar(ss[wt]+48),wt--);} } inline void print(LL x){ if (x<0) x=-x,putchar('-'); if (!x) putchar(48); else {for (wt=0;x;ss[++wt]=x%10,x/=10);for (;wt;putchar(ss[wt]+48),wt--);} } int n,m,a[300010],A[300010],B[300010]; struct data { int a,b,tag,sum; }tree[1200010]; const int mo=1000000009; void pre() { A[1]=1,A[2]=0; B[1]=0,B[2]=1; for (int i=3;i<=300005;i++) A[i]=(A[i-1]+A[i-2])%mo,B[i]=(B[i-1]+B[i-2])%mo; } int calc(int x,int y,int l) { //cout<<A[4]<<endl; return ((x*A[l+2]%mo+y*B[l+2]%mo)%mo-y+mo)%mo; } int F(int x,int y,int l) { return (x*A[l]%mo+y*B[l]%mo)%mo; } void Pushdown(int x,int l,int r) { //cout<<x<<" "<<l<<" "<<r<<endl; //cout<<"tree[x]="<<tree[x].a<<" "<<tree[x].b<<" "<<tree[x].tag<<endl; if (tree[x].tag) { int mid=l+r>>1; tree[x].tag=0; tree[x<<1].tag=1; tree[x<<1|1].tag=1; tree[x<<1].a=(tree[x<<1].a+tree[x].a)%mo; tree[x<<1].b=(tree[x<<1].b+tree[x].b)%mo; tree[x<<1].sum=(tree[x<<1].sum+calc(tree[x].a,tree[x].b,mid-l+1))%mo; //cout<<"mid+1="<<mid+1<<endl; //cout<<tree[x<<1|1].a<<" "<< F(tree[x].a,tree[x].b,mid-l+2)<<endl; tree[x<<1|1].a=(tree[x<<1|1].a+F(tree[x].a,tree[x].b,mid-l+2))%mo; //cout<<tree[x<<1|1].b<<" "<< F(tree[x].a,tree[x].b,mid-l+3)<<endl; tree[x<<1|1].b=(tree[x<<1|1].b+F(tree[x].a,tree[x].b,mid-l+3))%mo; tree[x<<1|1].sum=(tree[x<<1|1].sum+calc(F(tree[x].a,tree[x].b,mid-l+2),F(tree[x].a,tree[x].b,mid-l+3),r-mid))%mo; tree[x].a=0,tree[x].b=0; tree[x].sum=tree[x<<1].sum+tree[x<<1|1].sum; //cout<<tree[x<<1|1].a<<" "<<tree[x<<1|1].b<<endl; } } void change(int x,int l,int r,int lq,int rq,int a,int b) { //printf("%d %d %d %d %d\n",x,l,r,a,b); if (lq<=l&&rq>=r) { tree[x].a=(tree[x].a+a)%mo; tree[x].b=(tree[x].b+b)%mo; tree[x].sum=(tree[x].sum+calc(a,b,r-l+1))%mo; tree[x].tag=1; return ; } int mid=l+r>>1; Pushdown(x,l,r); if (lq<=mid) change(x<<1,l,mid,lq,rq,a,b); if (rq>mid) { if (lq<=mid) change(x<<1|1,mid+1,r,lq,rq,F(a,b,mid-lq+2),F(a,b,mid-lq+3)); else change(x<<1|1,mid+1,r,lq,rq,a,b); } //if (mid-l+1>=2) tree[x].a=tree[x<<1].a,tree[x].b=tree[x<<1].b; //else tree[x].a=tree[x<<1].a,tree[x].b=tree[x<<1|1].a; tree[x].sum=tree[x<<1].sum+tree[x<<1|1].sum; //printf("l=%d r=%d sum=%d\n",l,r,tree[x].sum); } int query(int x,int l,int r,int lq,int rq) { //printf("[%d,%d] a=%d b=%d l=%d sum=%d\n",l,r,tree[x].a,tree[x].b,r-l+1,tree[x].sum); if (lq<=l&&rq>=r&&(l==r||!tree[x].tag)) return tree[x].sum; int mid=l+r>>1,res=0; Pushdown(x,l,r); if (lq<=mid) res=(res+query(x<<1,l,mid,lq,rq))%mo; if (rq>mid) res=(res+query(x<<1|1,mid+1,r,lq,rq))%mo; tree[x].sum=tree[x<<1].sum+tree[x<<1|1].sum; return res; } int main() { read(n);read(m); pre(); memset(a,0,sizeof(a)); for (int i=1;i<=n;i++) read(a[i]),a[i]=(a[i]+a[i-1])%mo; memset(tree,0,sizeof(tree)); int x,y,z; while(m--) { read(x),read(y),read(z); if (x==1) change(1,1,n,y,z,1,1); else //print((query(1,1,n,y,z))%mo),puts(""); print((query(1,1,n,y,z)+a[z]-a[y-1]+mo)%mo),puts(""); } return 0; } /* 50 80 161 254 648 762 509 898 67 189 622 567 604 32 652 964 427 466 580 817 599 752 598 476 908 7 783 167 1000 117 737 559 534 33 670 855 988 366 241 980 500 308 277 110 86 719 779 69 708 550 24 714 1 6 42 2 38 41 */ |
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1 Comment
Xiejiadong · 2018年11月1日 at 下午6:35
评论测试。